1304103224401 has 4 divisors (see below), whose sum is σ = 1304146839204. Its totient is φ = 1304059609600.

The previous prime is 1304103224399. The next prime is 1304103224507. The reversal of 1304103224401 is 1044223014031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 880791635025 + 423311589376 = 938505^2 + 650624^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304103224401 - 2¹ = 1304103224399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304103224101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21762520 + ... + 21822361.

It is an arithmetic number, because the mean of its divisors is an integer number (326036709801).

Almost surely, 2^{1304103224401} is an apocalyptic number.

It is an amenable number.

1304103224401 is a deficient number, since it is larger than the sum of its proper divisors (43614803).

1304103224401 is an equidigital number, since it uses as much as digits as its factorization.

1304103224401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43614802.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1304103224401 its reverse (1044223014031), we get a palindrome (2348326238432).

The spelling of 1304103224401 in words is "one trillion, three hundred four billion, one hundred three million, two hundred twenty-four thousand, four hundred one".