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130411141397 is a prime number
BaseRepresentation
bin111100101110100011…
…1000001100100010101
3110110121120120101120222
41321131013001210111
54114040223011042
6135524323204125
712264465261215
oct1713507014425
9413546511528
10130411141397
1150341764809
1221336516645
13c3b4117374
146451d30245
1535d3ec82d2
hex1e5d1c1915

130411141397 has 2 divisors, whose sum is σ = 130411141398. Its totient is φ = 130411141396.

The previous prime is 130411141381. The next prime is 130411141433. The reversal of 130411141397 is 793141114031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105972385156 + 24438756241 = 325534^2 + 156329^2 .

It is a cyclic number.

It is not a de Polignac number, because 130411141397 - 24 = 130411141381 is a prime.

It is a super-3 number, since 3×1304111413973 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130411141327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205570698 + 65205570699.

It is an arithmetic number, because the mean of its divisors is an integer number (65205570699).

Almost surely, 2130411141397 is an apocalyptic number.

It is an amenable number.

130411141397 is a deficient number, since it is larger than the sum of its proper divisors (1).

130411141397 is an equidigital number, since it uses as much as digits as its factorization.

130411141397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 35.

The spelling of 130411141397 in words is "one hundred thirty billion, four hundred eleven million, one hundred forty-one thousand, three hundred ninety-seven".