Base | Representation |
---|---|
bin | 11101101001101110111001… |
… | …111011101010000001101011 |
3 | 122002202012010112212102020110 |
4 | 131221232321323222001223 |
5 | 114043124130111311133 |
6 | 1141210030010025403 |
7 | 36316620251205333 |
oct | 3551567173520153 |
9 | 562665115772213 |
10 | 130411211432043 |
11 | 3860a0a2049443 |
12 | 12762696a18263 |
13 | 579c955878789 |
14 | 242bd1734c0c3 |
15 | 1012465397c63 |
hex | 769bb9eea06b |
130411211432043 has 8 divisors (see below), whose sum is σ = 173881671610000. Its totient is φ = 86940779437728.
The previous prime is 130411211432039. The next prime is 130411211432087. The reversal of 130411211432043 is 340234112114031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130411211432043 - 22 = 130411211432039 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 130411211432043.
It is not an unprimeable number, because it can be changed into a prime (130411211432143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8917833 + ... + 18448581.
It is an arithmetic number, because the mean of its divisors is an integer number (21735208951250).
Almost surely, 2130411211432043 is an apocalyptic number.
130411211432043 is a deficient number, since it is larger than the sum of its proper divisors (43470460177957).
130411211432043 is an equidigital number, since it uses as much as digits as its factorization.
130411211432043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14091821.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 130411211432043 its reverse (340234112114031), we get a palindrome (470645323546074).
The spelling of 130411211432043 in words is "one hundred thirty trillion, four hundred eleven billion, two hundred eleven million, four hundred thirty-two thousand, forty-three".
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