130411313 has 2 divisors, whose sum is σ = 130411314. Its totient is φ = 130411312.

The previous prime is 130411297. The next prime is 130411349. The reversal of 130411313 is 313114031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113699569 + 16711744 = 10663^2 + 4088^2 .

It is an emirp because it is prime and its reverse (313114031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130411313 - 2⁴ = 130411297 is a prime.

It is a super-2 number, since 2×130411313² = 34014221116767938, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 130411291 and 130411300.

It is not a weakly prime, because it can be changed into another prime (130411363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205656 + 65205657.

It is an arithmetic number, because the mean of its divisors is an integer number (65205657).

Almost surely, 2^130411313 is an apocalyptic number.

It is an amenable number.

130411313 is a deficient number, since it is larger than the sum of its proper divisors (1).

130411313 is an equidigital number, since it uses as much as digits as its factorization.

130411313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 130411313 is about 11419.7772745356. Note that the first 3 decimals coincide. The cubic root of 130411313 is about 507.1134030711.

Adding to 130411313 its reverse (313114031), we get a palindrome (443525344).

The spelling of 130411313 in words is "one hundred thirty million, four hundred eleven thousand, three hundred thirteen".