Base | Representation |
---|---|
bin | 111100101110100011… |
… | …1110010111001000111 |
3 | 110110121120221122201201 |
4 | 1321131013302321013 |
5 | 4114040300442211 |
6 | 135524331403331 |
7 | 12264500062225 |
oct | 1713507627107 |
9 | 413546848651 |
10 | 130411343431 |
11 | 50341892586 |
12 | 213365b3547 |
13 | c3b4188305 |
14 | 6451d83b15 |
15 | 35d40180c1 |
hex | 1e5d1f2e47 |
130411343431 has 4 divisors (see below), whose sum is σ = 131274994864. Its totient is φ = 129547692000.
The previous prime is 130411343417. The next prime is 130411343441. The reversal of 130411343431 is 134343114031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130411343431 - 27 = 130411343303 is a prime.
It is a super-2 number, since 2×1304113434312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 130411343431.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130411343401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431825490 + ... + 431825791.
It is an arithmetic number, because the mean of its divisors is an integer number (32818748716).
Almost surely, 2130411343431 is an apocalyptic number.
130411343431 is a deficient number, since it is larger than the sum of its proper divisors (863651433).
130411343431 is an equidigital number, since it uses as much as digits as its factorization.
130411343431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 863651432.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 130411343431 its reverse (134343114031), we get a palindrome (264754457462).
The spelling of 130411343431 in words is "one hundred thirty billion, four hundred eleven million, three hundred forty-three thousand, four hundred thirty-one".
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