130411434010033 has 4 divisors (see below), whose sum is σ = 142267018920048. Its totient is φ = 118555849100020.

The previous prime is 130411434010009. The next prime is 130411434010087. The reversal of 130411434010033 is 330010434114031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130411434010033 - 2¹⁷ = 130411433878961 is a prime.

It is a super-2 number, since 2×130411434010033² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130411434009983 and 130411434010010.

It is not an unprimeable number, because it can be changed into a prime (130411434010433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5927792454991 + ... + 5927792455012.

It is an arithmetic number, because the mean of its divisors is an integer number (35566754730012).

Almost surely, 2^{130411434010033} is an apocalyptic number.

It is an amenable number.

130411434010033 is a deficient number, since it is larger than the sum of its proper divisors (11855584910015).

130411434010033 is a wasteful number, since it uses less digits than its factorization.

130411434010033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11855584910014.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 130411434010033 its reverse (330010434114031), we get a palindrome (460421868124064).

The spelling of 130411434010033 in words is "one hundred thirty trillion, four hundred eleven billion, four hundred thirty-four million, ten thousand, thirty-three".