Base | Representation |
---|---|
bin | 11101101001101111000111… |
… | …001100101110010111110111 |
3 | 122002202012201001200112221022 |
4 | 131221233013030232113313 |
5 | 114043130104101310403 |
6 | 1141210104040411355 |
7 | 36316625623120061 |
oct | 3551570714562767 |
9 | 562665631615838 |
10 | 130411434010103 |
11 | 3860a1a6752654 |
12 | 12762739476b5b |
13 | 579c98ca0977c |
14 | 242bd38b2a731 |
15 | 1012479bb1d38 |
hex | 769bc732e5f7 |
130411434010103 has 2 divisors, whose sum is σ = 130411434010104. Its totient is φ = 130411434010102.
The previous prime is 130411434010087. The next prime is 130411434010177. The reversal of 130411434010103 is 301010434114031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130411434010103 - 24 = 130411434010087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130411434010183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65205717005051 + 65205717005052.
It is an arithmetic number, because the mean of its divisors is an integer number (65205717005052).
Almost surely, 2130411434010103 is an apocalyptic number.
130411434010103 is a deficient number, since it is larger than the sum of its proper divisors (1).
130411434010103 is an equidigital number, since it uses as much as digits as its factorization.
130411434010103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 130411434010103 its reverse (301010434114031), we get a palindrome (431421868124134).
The spelling of 130411434010103 in words is "one hundred thirty trillion, four hundred eleven billion, four hundred thirty-four million, ten thousand, one hundred three".
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