Base | Representation |
---|---|
bin | 1011110111000110101100… |
… | …0010101001010011010111 |
3 | 1201011201220202220120010020 |
4 | 2331301223002221103113 |
5 | 3202132104020104411 |
6 | 43423033110000223 |
7 | 2514126660540612 |
oct | 275615302512327 |
9 | 51151822816106 |
10 | 13041316566231 |
11 | 41788782404a8 |
12 | 15675b2646073 |
13 | 737a38726145 |
14 | 3312bb3c7179 |
15 | 17937ba32606 |
hex | bdc6b0a94d7 |
13041316566231 has 4 divisors (see below), whose sum is σ = 17388422088312. Its totient is φ = 8694211044152.
The previous prime is 13041316566209. The next prime is 13041316566259. The reversal of 13041316566231 is 13266561314031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13041316566231 - 25 = 13041316566199 is a prime.
It is a super-2 number, since 2×130413165662312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13041316566431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173552761036 + ... + 2173552761041.
It is an arithmetic number, because the mean of its divisors is an integer number (4347105522078).
Almost surely, 213041316566231 is an apocalyptic number.
13041316566231 is a deficient number, since it is larger than the sum of its proper divisors (4347105522081).
13041316566231 is an equidigital number, since it uses as much as digits as its factorization.
13041316566231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4347105522080.
The product of its (nonzero) digits is 233280, while the sum is 42.
The spelling of 13041316566231 in words is "thirteen trillion, forty-one billion, three hundred sixteen million, five hundred sixty-six thousand, two hundred thirty-one".
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