Search a number
-
+
130413405673 = 600721710239
BaseRepresentation
bin111100101110100111…
…1101010010111101001
3110110121201211102121001
41321131033222113221
54114041312440143
6135524443515001
712264523441465
oct1713517522751
9413551742531
10130413405673
1150342a70a11
1221337228a61
13c3b472ab85
14645235d4a5
1535d42c414d
hex1e5d3ea5e9

130413405673 has 4 divisors (see below), whose sum is σ = 130435121920. Its totient is φ = 130391689428.

The previous prime is 130413405659. The next prime is 130413405677. The reversal of 130413405673 is 376504314031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 376504314031 = 478778651413.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130413405673 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130413405677) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10849113 + ... + 10861126.

It is an arithmetic number, because the mean of its divisors is an integer number (32608780480).

Almost surely, 2130413405673 is an apocalyptic number.

It is an amenable number.

130413405673 is a deficient number, since it is larger than the sum of its proper divisors (21716247).

130413405673 is an equidigital number, since it uses as much as digits as its factorization.

130413405673 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21716246.

The product of its (nonzero) digits is 90720, while the sum is 37.

The spelling of 130413405673 in words is "one hundred thirty billion, four hundred thirteen million, four hundred five thousand, six hundred seventy-three".

Divisors: 1 6007 21710239 130413405673