13041380698 has 4 divisors (see below), whose sum is σ = 19562071050. Its totient is φ = 6520690348.

The previous prime is 13041380647. The next prime is 13041380701. The reversal of 13041380698 is 89608314031.

13041380698 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 89608314031 = 47 ⋅1906559873.

It can be written as a sum of positive squares in only one way, i.e., 9876980689 + 3164400009 = 99383^2 + 56253^2 .

It is a super-3 number, since 3×13041380698³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3260345173 + ... + 3260345176.

Almost surely, 2^13041380698 is an apocalyptic number.

13041380698 is a deficient number, since it is larger than the sum of its proper divisors (6520690352).

13041380698 is an equidigital number, since it uses as much as digits as its factorization.

13041380698 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6520690351.

The product of its (nonzero) digits is 124416, while the sum is 43.

The spelling of 13041380698 in words is "thirteen billion, forty-one million, three hundred eighty thousand, six hundred ninety-eight".