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130414013431411 is a prime number
BaseRepresentation
bin11101101001110001100000…
…111100011011111001110011
3122002202110100211022201202211
4131221301200330123321303
5114043200344414301121
61141211212022352551
736320046553621603
oct3551614074337163
9562673324281684
10130414013431411
11386102aa771aa6
121276313928b757
13579ccb1225a78
14242c101532c03
15101257b379ce1
hex769c60f1be73

130414013431411 has 2 divisors, whose sum is σ = 130414013431412. Its totient is φ = 130414013431410.

The previous prime is 130414013431357. The next prime is 130414013431417. The reversal of 130414013431411 is 114134310414031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130414013431411 - 241 = 128214990175859 is a prime.

It is not a weakly prime, because it can be changed into another prime (130414013431417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65207006715705 + 65207006715706.

It is an arithmetic number, because the mean of its divisors is an integer number (65207006715706).

Almost surely, 2130414013431411 is an apocalyptic number.

130414013431411 is a deficient number, since it is larger than the sum of its proper divisors (1).

130414013431411 is an equidigital number, since it uses as much as digits as its factorization.

130414013431411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 130414013431411 its reverse (114134310414031), we get a palindrome (244548323845442).

The spelling of 130414013431411 in words is "one hundred thirty trillion, four hundred fourteen billion, thirteen million, four hundred thirty-one thousand, four hundred eleven".