Base | Representation |
---|---|
bin | 10010111110100100110… |
… | …111111000001110101011 |
3 | 11121200012211202022212212 |
4 | 102332210313320032223 |
5 | 132331340121433342 |
6 | 2435040355555335 |
7 | 163135556213534 |
oct | 22764467701653 |
9 | 4550184668785 |
10 | 1304141202347 |
11 | 4630a0789875 |
12 | 1909022bbb4b |
13 | 95c98057529 |
14 | 4719957768b |
15 | 23dcc78d182 |
hex | 12fa4df83ab |
1304141202347 has 2 divisors, whose sum is σ = 1304141202348. Its totient is φ = 1304141202346.
The previous prime is 1304141202337. The next prime is 1304141202431. The reversal of 1304141202347 is 7432021414031.
It is a weak prime.
It is an emirp because it is prime and its reverse (7432021414031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304141202347 - 210 = 1304141201323 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304141202317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652070601173 + 652070601174.
It is an arithmetic number, because the mean of its divisors is an integer number (652070601174).
Almost surely, 21304141202347 is an apocalyptic number.
1304141202347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304141202347 is an equidigital number, since it uses as much as digits as its factorization.
1304141202347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 1304141202347 its reverse (7432021414031), we get a palindrome (8736162616378).
The spelling of 1304141202347 in words is "one trillion, three hundred four billion, one hundred forty-one million, two hundred two thousand, three hundred forty-seven".
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