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130414232131102 = 265207116065551
BaseRepresentation
bin11101101001110001101101…
…111110101101011000011110
3122002202110221001211211100101
4131221301231332231120132
5114043201321411143402
61141211245434051314
736320055150551203
oct3551615576553036
9562673831754311
10130414232131102
1138610402167347
121276319a579b3a
1357a001762967a
14242c1225c1caa
151012590679b87
hex769c6dfad61e

130414232131102 has 4 divisors (see below), whose sum is σ = 195621348196656. Its totient is φ = 65207116065550.

The previous prime is 130414232131097. The next prime is 130414232131103. The reversal of 130414232131102 is 201131232414031.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130414232131103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32603558032774 + ... + 32603558032777.

It is an arithmetic number, because the mean of its divisors is an integer number (48905337049164).

Almost surely, 2130414232131102 is an apocalyptic number.

130414232131102 is a deficient number, since it is larger than the sum of its proper divisors (65207116065554).

130414232131102 is an equidigital number, since it uses as much as digits as its factorization.

130414232131102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65207116065553.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 130414232131102 its reverse (201131232414031), we get a palindrome (331545464545133).

The spelling of 130414232131102 in words is "one hundred thirty trillion, four hundred fourteen billion, two hundred thirty-two million, one hundred thirty-one thousand, one hundred two".

Divisors: 1 2 65207116065551 130414232131102