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130414302133 is a prime number
BaseRepresentation
bin111100101110101001…
…1000101001110110101
3110110121210111222022021
41321131103011032311
54114042030132013
6135524515033141
712264534164203
oct1713523051665
9413553458267
10130414302133
1150343523495
122133759b7b1
13c3b4982c1b
146452514073
1535d43eea8d
hex1e5d4c53b5

130414302133 has 2 divisors, whose sum is σ = 130414302134. Its totient is φ = 130414302132.

The previous prime is 130414302089. The next prime is 130414302157. The reversal of 130414302133 is 331203414031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103798663684 + 26615638449 = 322178^2 + 163143^2 .

It is a cyclic number.

It is not a de Polignac number, because 130414302133 - 229 = 129877431221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130414302098 and 130414302107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130414302533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65207151066 + 65207151067.

It is an arithmetic number, because the mean of its divisors is an integer number (65207151067).

Almost surely, 2130414302133 is an apocalyptic number.

It is an amenable number.

130414302133 is a deficient number, since it is larger than the sum of its proper divisors (1).

130414302133 is an equidigital number, since it uses as much as digits as its factorization.

130414302133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 130414302133 its reverse (331203414031), we get a palindrome (461617716164).

The spelling of 130414302133 in words is "one hundred thirty billion, four hundred fourteen million, three hundred two thousand, one hundred thirty-three".