130415255133 has 4 divisors (see below), whose sum is σ = 173887006848. Its totient is φ = 86943503420.

The previous prime is 130415255107. The next prime is 130415255137. The reversal of 130415255133 is 331552514031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130415255133 - 2⁵ = 130415255101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130415255094 and 130415255103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130415255137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21735875853 + ... + 21735875858.

It is an arithmetic number, because the mean of its divisors is an integer number (43471751712).

Almost surely, 2^130415255133 is an apocalyptic number.

It is an amenable number.

130415255133 is a deficient number, since it is larger than the sum of its proper divisors (43471751715).

130415255133 is an equidigital number, since it uses as much as digits as its factorization.

130415255133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43471751714.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 130415255133 its reverse (331552514031), we get a palindrome (461967769164).

The spelling of 130415255133 in words is "one hundred thirty billion, four hundred fifteen million, two hundred fifty-five thousand, one hundred thirty-three".