Base | Representation |
---|---|
bin | 11101101001111000010011… |
… | …010010000001110001100101 |
3 | 122002210011011200001020222121 |
4 | 131221320103102001301211 |
5 | 114043310310400401201 |
6 | 1141214415051425541 |
7 | 36320425256066605 |
oct | 3551702322016145 |
9 | 562704150036877 |
10 | 130421300403301 |
11 | 386133aa001916 |
12 | 127646317552b1 |
13 | 57a08a2b1785b |
14 | 242c5d3230c05 |
15 | 1012855e7c9a1 |
hex | 769e13481c65 |
130421300403301 has 2 divisors, whose sum is σ = 130421300403302. Its totient is φ = 130421300403300.
The previous prime is 130421300403283. The next prime is 130421300403313. The reversal of 130421300403301 is 103304003124031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127501337139201 + 2919963264100 = 11291649^2 + 1708790^2 .
It is a cyclic number.
It is not a de Polignac number, because 130421300403301 - 215 = 130421300370533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130421300463301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65210650201650 + 65210650201651.
It is an arithmetic number, because the mean of its divisors is an integer number (65210650201651).
Almost surely, 2130421300403301 is an apocalyptic number.
It is an amenable number.
130421300403301 is a deficient number, since it is larger than the sum of its proper divisors (1).
130421300403301 is an equidigital number, since it uses as much as digits as its factorization.
130421300403301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 130421300403301 its reverse (103304003124031), we get a palindrome (233725303527332).
The spelling of 130421300403301 in words is "one hundred thirty trillion, four hundred twenty-one billion, three hundred million, four hundred three thousand, three hundred one".
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