1304220305147 has 2 divisors, whose sum is σ = 1304220305148. Its totient is φ = 1304220305146.

The previous prime is 1304220305117. The next prime is 1304220305149. The reversal of 1304220305147 is 7415030224031.

It is a strong prime.

It is an emirp because it is prime and its reverse (7415030224031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304220305147 - 2¹² = 1304220301051 is a prime.

Together with 1304220305149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1304220305149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652110152573 + 652110152574.

It is an arithmetic number, because the mean of its divisors is an integer number (652110152574).

Almost surely, 2^{1304220305147} is an apocalyptic number.

1304220305147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304220305147 is an equidigital number, since it uses as much as digits as its factorization.

1304220305147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 32.

Adding to 1304220305147 its reverse (7415030224031), we get a palindrome (8719250529178).

The spelling of 1304220305147 in words is "one trillion, three hundred four billion, two hundred twenty million, three hundred five thousand, one hundred forty-seven".