Base | Representation |
---|---|
bin | 10010111110101001101… |
… | …100111100111010010101 |
3 | 11121200102111012122201121 |
4 | 102332221230330322111 |
5 | 132332021342132041 |
6 | 2435052412323541 |
7 | 163140561663403 |
oct | 22765154747225 |
9 | 4550374178647 |
10 | 1304222224021 |
11 | 463132498632 |
12 | 1909254735b1 |
13 | 95caba84952 |
14 | 471a6228473 |
15 | 23dd49447d1 |
hex | 12fa9b3ce95 |
1304222224021 has 2 divisors, whose sum is σ = 1304222224022. Its totient is φ = 1304222224020.
The previous prime is 1304222224003. The next prime is 1304222224033. The reversal of 1304222224021 is 1204222224031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1299292218225 + 4930005796 = 1139865^2 + 70214^2 .
It is an emirp because it is prime and its reverse (1204222224031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1304222224021 - 215 = 1304222191253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304222224421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652111112010 + 652111112011.
It is an arithmetic number, because the mean of its divisors is an integer number (652111112011).
Almost surely, 21304222224021 is an apocalyptic number.
It is an amenable number.
1304222224021 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304222224021 is an equidigital number, since it uses as much as digits as its factorization.
1304222224021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 1304222224021 its reverse (1204222224031), we get a palindrome (2508444448052).
The spelling of 1304222224021 in words is "one trillion, three hundred four billion, two hundred twenty-two million, two hundred twenty-four thousand, twenty-one".
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