Base | Representation |
---|---|
bin | 11101101001111001010000… |
… | …101110010100011111000111 |
3 | 122002210020211111201200120211 |
4 | 131221321100232110133013 |
5 | 114043314413243331101 |
6 | 1141215105233540251 |
7 | 36320462644011652 |
oct | 3551712056243707 |
9 | 562706744650524 |
10 | 130422331230151 |
11 | 38613888970334 |
12 | 1276487aa14687 |
13 | 57a0a0855917c |
14 | 242c6900c4899 |
15 | 10128b66ecc51 |
hex | 769e50b947c7 |
130422331230151 has 2 divisors, whose sum is σ = 130422331230152. Its totient is φ = 130422331230150.
The previous prime is 130422331230119. The next prime is 130422331230181. The reversal of 130422331230151 is 151032133224031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130422331230151 - 25 = 130422331230119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130422331230101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65211165615075 + 65211165615076.
It is an arithmetic number, because the mean of its divisors is an integer number (65211165615076).
Almost surely, 2130422331230151 is an apocalyptic number.
130422331230151 is a deficient number, since it is larger than the sum of its proper divisors (1).
130422331230151 is an equidigital number, since it uses as much as digits as its factorization.
130422331230151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 130422331230151 its reverse (151032133224031), we get a palindrome (281454464454182).
The spelling of 130422331230151 in words is "one hundred thirty trillion, four hundred twenty-two billion, three hundred thirty-one million, two hundred thirty thousand, one hundred fifty-one".
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