Base | Representation |
---|---|
bin | 111100101110111010… |
… | …0101100011011001101 |
3 | 110110122102002122010021 |
4 | 1321131310230123031 |
5 | 4114101304112141 |
6 | 135525431542141 |
7 | 12265002113116 |
oct | 1713564543315 |
9 | 413572078107 |
10 | 130423113421 |
11 | 503484a1547 |
12 | 2133a52a951 |
13 | c3b67496c3 |
14 | 645376920d |
15 | 35d50906d1 |
hex | 1e5dd2c6cd |
130423113421 has 2 divisors, whose sum is σ = 130423113422. Its totient is φ = 130423113420.
The previous prime is 130423113397. The next prime is 130423113463. The reversal of 130423113421 is 124311324031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115286732521 + 15136380900 = 339539^2 + 123030^2 .
It is an emirp because it is prime and its reverse (124311324031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130423113421 - 229 = 129886242509 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130423117421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65211556710 + 65211556711.
It is an arithmetic number, because the mean of its divisors is an integer number (65211556711).
Almost surely, 2130423113421 is an apocalyptic number.
It is an amenable number.
130423113421 is a deficient number, since it is larger than the sum of its proper divisors (1).
130423113421 is an equidigital number, since it uses as much as digits as its factorization.
130423113421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 130423113421 its reverse (124311324031), we get a palindrome (254734437452).
The spelling of 130423113421 in words is "one hundred thirty billion, four hundred twenty-three million, one hundred thirteen thousand, four hundred twenty-one".
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