Base | Representation |
---|---|
bin | 10010111110101010110… |
… | …100101000011001010001 |
3 | 11121200110210120022012211 |
4 | 102332222310220121101 |
5 | 132332041144424403 |
6 | 2435054323152121 |
7 | 163141210463614 |
oct | 22765264503121 |
9 | 4550423508184 |
10 | 1304241014353 |
11 | 463142062032 |
12 | 19092b815641 |
13 | 95cb29335a4 |
14 | 471a891a17b |
15 | 23dd640706d |
hex | 12faad28651 |
1304241014353 has 2 divisors, whose sum is σ = 1304241014354. Its totient is φ = 1304241014352.
The previous prime is 1304241014317. The next prime is 1304241014389. The reversal of 1304241014353 is 3534101424031.
It is a balanced prime because it is at equal distance from previous prime (1304241014317) and next prime (1304241014389).
It can be written as a sum of positive squares in only one way, i.e., 1286788490689 + 17452523664 = 1134367^2 + 132108^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304241014353 - 29 = 1304241013841 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304241014303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120507176 + 652120507177.
It is an arithmetic number, because the mean of its divisors is an integer number (652120507177).
Almost surely, 21304241014353 is an apocalyptic number.
It is an amenable number.
1304241014353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304241014353 is an equidigital number, since it uses as much as digits as its factorization.
1304241014353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 1304241014353 its reverse (3534101424031), we get a palindrome (4838342438384).
The spelling of 1304241014353 in words is "one trillion, three hundred four billion, two hundred forty-one million, fourteen thousand, three hundred fifty-three".
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