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1304241114331 is a prime number
BaseRepresentation
bin10010111110101010110…
…101000000110011011011
311121200110210202101100201
4102332222311000303123
5132332041211124311
62435054325243031
7163141211361241
oct22765265006333
94550423671321
101304241114331
11463142120161
1219092b863477
1395cb2969c4c
14471a8944791
1523dd64269c1
hex12faad40cdb

1304241114331 has 2 divisors, whose sum is σ = 1304241114332. Its totient is φ = 1304241114330.

The previous prime is 1304241114329. The next prime is 1304241114343. The reversal of 1304241114331 is 1334111424031.

It is a weak prime.

It is an emirp because it is prime and its reverse (1334111424031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1304241114331 - 21 = 1304241114329 is a prime.

It is a super-2 number, since 2×13042411143312 (a number of 25 digits) contains 22 as substring.

Together with 1304241114329, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1304241114331.

It is not a weakly prime, because it can be changed into another prime (1302241114331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120557165 + 652120557166.

It is an arithmetic number, because the mean of its divisors is an integer number (652120557166).

Almost surely, 21304241114331 is an apocalyptic number.

1304241114331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304241114331 is an equidigital number, since it uses as much as digits as its factorization.

1304241114331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1304241114331 its reverse (1334111424031), we get a palindrome (2638352538362).

The spelling of 1304241114331 in words is "one trillion, three hundred four billion, two hundred forty-one million, one hundred fourteen thousand, three hundred thirty-one".