Base | Representation |
---|---|
bin | 10010111110101010110… |
… | …101000010001011111111 |
3 | 11121200110210202200010122 |
4 | 102332222311002023333 |
5 | 132332041211314444 |
6 | 2435054325325155 |
7 | 163141211413616 |
oct | 22765265021377 |
9 | 4550423680118 |
10 | 1304241119999 |
11 | 463142124444 |
12 | 19092b8667bb |
13 | 95cb296c6bc |
14 | 471a894687d |
15 | 23dd64284ee |
hex | 12faad422ff |
1304241119999 has 2 divisors, whose sum is σ = 1304241120000. Its totient is φ = 1304241119998.
The previous prime is 1304241119971. The next prime is 1304241120029. The reversal of 1304241119999 is 9999111424031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1304241119999 - 236 = 1235521643263 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1304241119999.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304241119959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652120559999 + 652120560000.
It is an arithmetic number, because the mean of its divisors is an integer number (652120560000).
Almost surely, 21304241119999 is an apocalyptic number.
1304241119999 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304241119999 is an equidigital number, since it uses as much as digits as its factorization.
1304241119999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 629856, while the sum is 53.
The spelling of 1304241119999 in words is "one trillion, three hundred four billion, two hundred forty-one million, one hundred nineteen thousand, nine hundred ninety-nine".
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