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1304243140111 = 3733013493811
BaseRepresentation
bin10010111110101010111…
…100101111011000001111
311121200110221120022012121
4102332222330233120033
5132332042220440421
62435054440513411
7163141234526302
oct22765274573017
94550427508177
101304243140111
1146314328415a
1219093047b867
1395cb31c9032
14471a8d10b39
1523dd66c6d41
hex12faaf2f60f

1304243140111 has 4 divisors (see below), whose sum is σ = 1304247007224. Its totient is φ = 1304239273000.

The previous prime is 1304243140103. The next prime is 1304243140127. The reversal of 1304243140111 is 1110413424031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1304243140111 - 23 = 1304243140103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304243840111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1373605 + ... + 2120206.

It is an arithmetic number, because the mean of its divisors is an integer number (326061751806).

Almost surely, 21304243140111 is an apocalyptic number.

1304243140111 is a deficient number, since it is larger than the sum of its proper divisors (3867113).

1304243140111 is an equidigital number, since it uses as much as digits as its factorization.

1304243140111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3867112.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1304243140111 its reverse (1110413424031), we get a palindrome (2414656564142).

The spelling of 1304243140111 in words is "one trillion, three hundred four billion, two hundred forty-three million, one hundred forty thousand, one hundred eleven".

Divisors: 1 373301 3493811 1304243140111