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130425135551 = 143391015447
BaseRepresentation
bin111100101110111110…
…0011010000110111111
3110110122112220100221222
41321131330122012333
54114102313314201
6135525543143555
712265025234414
oct1713574320677
9413575810858
10130425135551
1150349652827
122133b144bbb
13c3b6ca6c29
146453b3410b
1535d533e91b
hex1e5df1a1bf

130425135551 has 4 divisors (see below), whose sum is σ = 130516152432. Its totient is φ = 130334118672.

The previous prime is 130425135539. The next prime is 130425135623. The reversal of 130425135551 is 155531524031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130425135551 - 230 = 129351393727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130425135521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45506291 + ... + 45509156.

It is an arithmetic number, because the mean of its divisors is an integer number (32629038108).

Almost surely, 2130425135551 is an apocalyptic number.

130425135551 is a deficient number, since it is larger than the sum of its proper divisors (91016881).

130425135551 is an equidigital number, since it uses as much as digits as its factorization.

130425135551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91016880.

The product of its (nonzero) digits is 45000, while the sum is 35.

Adding to 130425135551 its reverse (155531524031), we get a palindrome (285956659582).

The spelling of 130425135551 in words is "one hundred thirty billion, four hundred twenty-five million, one hundred thirty-five thousand, five hundred fifty-one".

Divisors: 1 1433 91015447 130425135551