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130425631075631 is a prime number
BaseRepresentation
bin11101101001111100010101…
…011010001110110100101111
3122002210120100110222012121002
4131221330111122032310233
5114043343143023410011
61141220412513030515
736320640503151503
oct3551742532166457
9562716313865532
10130425631075631
113861522160a061
121276543bb5543b
1357a11130b6068
14242c8c4460303
151012a0b26ec3b
hex769f1568ed2f

130425631075631 has 2 divisors, whose sum is σ = 130425631075632. Its totient is φ = 130425631075630.

The previous prime is 130425631075577. The next prime is 130425631075679. The reversal of 130425631075631 is 136570136524031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130425631075631 - 214 = 130425631059247 is a prime.

It is a super-2 number, since 2×1304256310756312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130425631075231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65212815537815 + 65212815537816.

It is an arithmetic number, because the mean of its divisors is an integer number (65212815537816).

Almost surely, 2130425631075631 is an apocalyptic number.

130425631075631 is a deficient number, since it is larger than the sum of its proper divisors (1).

130425631075631 is an equidigital number, since it uses as much as digits as its factorization.

130425631075631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 47.

Adding to 130425631075631 its reverse (136570136524031), we get a palindrome (266995767599662).

The spelling of 130425631075631 in words is "one hundred thirty trillion, four hundred twenty-five billion, six hundred thirty-one million, seventy-five thousand, six hundred thirty-one".