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13042699469 is a prime number
BaseRepresentation
bin11000010010110011…
…11100110011001101
31020122222010210010022
430021121330303031
5203202412340334
65554114151525
7641132054612
oct141131746315
936588123108
1013042699469
11559329a178
12263bb825a5
1312cb1a2167
148ba2c2509
1551508882e
hex30967cccd

13042699469 has 2 divisors, whose sum is σ = 13042699470. Its totient is φ = 13042699468.

The previous prime is 13042699433. The next prime is 13042699513. The reversal of 13042699469 is 96499624031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11872717444 + 1169982025 = 108962^2 + 34205^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13042699469 is a prime.

It is a super-2 number, since 2×130426994692 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13042699469.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13042699429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521349734 + 6521349735.

It is an arithmetic number, because the mean of its divisors is an integer number (6521349735).

Almost surely, 213042699469 is an apocalyptic number.

It is an amenable number.

13042699469 is a deficient number, since it is larger than the sum of its proper divisors (1).

13042699469 is an equidigital number, since it uses as much as digits as its factorization.

13042699469 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2519424, while the sum is 53.

The spelling of 13042699469 in words is "thirteen billion, forty-two million, six hundred ninety-nine thousand, four hundred sixty-nine".