Base | Representation |
---|---|
bin | 111100101111001001… |
… | …1101000101001110101 |
3 | 110110122222100201100021 |
4 | 1321132103220221311 |
5 | 4114110343140222 |
6 | 135530321445141 |
7 | 12265131054313 |
oct | 1713623505165 |
9 | 413588321307 |
10 | 130431224437 |
11 | 50352031468 |
12 | 213411a07b1 |
13 | c3b8329517 |
14 | 645487b0b3 |
15 | 35d5b43ac7 |
hex | 1e5e4e8a75 |
130431224437 has 2 divisors, whose sum is σ = 130431224438. Its totient is φ = 130431224436.
The previous prime is 130431224369. The next prime is 130431224459. The reversal of 130431224437 is 734422134031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128730981681 + 1700242756 = 358791^2 + 41234^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130431224437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130431224537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215612218 + 65215612219.
It is an arithmetic number, because the mean of its divisors is an integer number (65215612219).
Almost surely, 2130431224437 is an apocalyptic number.
It is an amenable number.
130431224437 is a deficient number, since it is larger than the sum of its proper divisors (1).
130431224437 is an equidigital number, since it uses as much as digits as its factorization.
130431224437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 34.
Adding to 130431224437 its reverse (734422134031), we get a palindrome (864853358468).
The spelling of 130431224437 in words is "one hundred thirty billion, four hundred thirty-one million, two hundred twenty-four thousand, four hundred thirty-seven".
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