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130431244223353 is a prime number
BaseRepresentation
bin11101101010000001100011…
…111110101100001101111001
3122002211002211200002122201011
4131222001203332230031321
5114043441142010121403
61141223141510153521
736321226552134613
oct3552014376541571
9562732750078634
10130431244223353
1138617642035017
12127665479528a1
1357a17c8c94a48
14242cc97b2bdb3
151012c38e3ea6d
hex76a063fac379

130431244223353 has 2 divisors, whose sum is σ = 130431244223354. Its totient is φ = 130431244223352.

The previous prime is 130431244223327. The next prime is 130431244223509. The reversal of 130431244223353 is 353322442134031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128911317703744 + 1519926519609 = 11353912^2 + 1232853^2 .

It is a cyclic number.

It is not a de Polignac number, because 130431244223353 - 29 = 130431244222841 is a prime.

It is not a weakly prime, because it can be changed into another prime (130431244224353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215622111676 + 65215622111677.

It is an arithmetic number, because the mean of its divisors is an integer number (65215622111677).

Almost surely, 2130431244223353 is an apocalyptic number.

It is an amenable number.

130431244223353 is a deficient number, since it is larger than the sum of its proper divisors (1).

130431244223353 is an equidigital number, since it uses as much as digits as its factorization.

130431244223353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 622080, while the sum is 40.

Adding to 130431244223353 its reverse (353322442134031), we get a palindrome (483753686357384).

The spelling of 130431244223353 in words is "one hundred thirty trillion, four hundred thirty-one billion, two hundred forty-four million, two hundred twenty-three thousand, three hundred fifty-three".