Base | Representation |
---|---|
bin | 11101101010000001100011… |
… | …111110101100001101111001 |
3 | 122002211002211200002122201011 |
4 | 131222001203332230031321 |
5 | 114043441142010121403 |
6 | 1141223141510153521 |
7 | 36321226552134613 |
oct | 3552014376541571 |
9 | 562732750078634 |
10 | 130431244223353 |
11 | 38617642035017 |
12 | 127665479528a1 |
13 | 57a17c8c94a48 |
14 | 242cc97b2bdb3 |
15 | 1012c38e3ea6d |
hex | 76a063fac379 |
130431244223353 has 2 divisors, whose sum is σ = 130431244223354. Its totient is φ = 130431244223352.
The previous prime is 130431244223327. The next prime is 130431244223509. The reversal of 130431244223353 is 353322442134031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128911317703744 + 1519926519609 = 11353912^2 + 1232853^2 .
It is a cyclic number.
It is not a de Polignac number, because 130431244223353 - 29 = 130431244222841 is a prime.
It is not a weakly prime, because it can be changed into another prime (130431244224353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65215622111676 + 65215622111677.
It is an arithmetic number, because the mean of its divisors is an integer number (65215622111677).
Almost surely, 2130431244223353 is an apocalyptic number.
It is an amenable number.
130431244223353 is a deficient number, since it is larger than the sum of its proper divisors (1).
130431244223353 is an equidigital number, since it uses as much as digits as its factorization.
130431244223353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 130431244223353 its reverse (353322442134031), we get a palindrome (483753686357384).
The spelling of 130431244223353 in words is "one hundred thirty trillion, four hundred thirty-one billion, two hundred forty-four million, two hundred twenty-three thousand, three hundred fifty-three".
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