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1304321004361 is a prime number
BaseRepresentation
bin10010111110101111100…
…101110001001101001001
311121200200101002012212201
4102332233211301031021
5132332222134114421
62435110301440201
7163143201415624
oct22765745611511
94550611065781
101304321004361
11463183226781
12190952570061
1395cc638c25b
14471b53bcdbb
1523ddd457b91
hex12faf971349

1304321004361 has 2 divisors, whose sum is σ = 1304321004362. Its totient is φ = 1304321004360.

The previous prime is 1304321004323. The next prime is 1304321004373. The reversal of 1304321004361 is 1634001234031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1066634528400 + 237686475961 = 1032780^2 + 487531^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304321004361 is a prime.

It is not a weakly prime, because it can be changed into another prime (1304321004391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652160502180 + 652160502181.

It is an arithmetic number, because the mean of its divisors is an integer number (652160502181).

Almost surely, 21304321004361 is an apocalyptic number.

It is an amenable number.

1304321004361 is a deficient number, since it is larger than the sum of its proper divisors (1).

1304321004361 is an equidigital number, since it uses as much as digits as its factorization.

1304321004361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1304321004361 its reverse (1634001234031), we get a palindrome (2938322238392).

The spelling of 1304321004361 in words is "one trillion, three hundred four billion, three hundred twenty-one million, four thousand, three hundred sixty-one".