Base | Representation |
---|---|
bin | 10010111110101111101… |
… | …011001010110111111001 |
3 | 11121200200110202011001211 |
4 | 102332233223022313321 |
5 | 132332223014421332 |
6 | 2435110352043121 |
7 | 163143216433525 |
oct | 22765753126771 |
9 | 4550613664054 |
10 | 1304322420217 |
11 | 463184003503 |
12 | 190952b334a1 |
13 | 95cc676683b |
14 | 471b566ad85 |
15 | 23ddd637447 |
hex | 12fafacadf9 |
1304322420217 has 2 divisors, whose sum is σ = 1304322420218. Its totient is φ = 1304322420216.
The previous prime is 1304322420209. The next prime is 1304322420221. The reversal of 1304322420217 is 7120242234031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 896498410896 + 407824009321 = 946836^2 + 638611^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304322420217 - 23 = 1304322420209 is a prime.
It is not a weakly prime, because it can be changed into another prime (1304322420287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652161210108 + 652161210109.
It is an arithmetic number, because the mean of its divisors is an integer number (652161210109).
Almost surely, 21304322420217 is an apocalyptic number.
It is an amenable number.
1304322420217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304322420217 is an equidigital number, since it uses as much as digits as its factorization.
1304322420217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 1304322420217 its reverse (7120242234031), we get a palindrome (8424564654248).
The spelling of 1304322420217 in words is "one trillion, three hundred four billion, three hundred twenty-two million, four hundred twenty thousand, two hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •