Base | Representation |
---|---|
bin | 11000010010111000… |
… | …00011011101100001 |
3 | 1020200000011210201220 |
4 | 30021130003131201 |
5 | 203203033013131 |
6 | 5554134045253 |
7 | 641136542652 |
oct | 141134033541 |
9 | 36600153656 |
10 | 13043251041 |
11 | 5593636617 |
12 | 26401a9829 |
13 | 12cb336232 |
14 | 8ba3c7529 |
15 | 515146e96 |
hex | 309703761 |
13043251041 has 4 divisors (see below), whose sum is σ = 17391001392. Its totient is φ = 8695500692.
The previous prime is 13043251021. The next prime is 13043251097. The reversal of 13043251041 is 14015234031.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14015234031 = 3 ⋅4671744677.
It is a cyclic number.
It is not a de Polignac number, because 13043251041 - 29 = 13043250529 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13043251021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173875171 + ... + 2173875176.
It is an arithmetic number, because the mean of its divisors is an integer number (4347750348).
Almost surely, 213043251041 is an apocalyptic number.
It is an amenable number.
13043251041 is a deficient number, since it is larger than the sum of its proper divisors (4347750351).
13043251041 is an equidigital number, since it uses as much as digits as its factorization.
13043251041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4347750350.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 13043251041 its reverse (14015234031), we get a palindrome (27058485072).
The spelling of 13043251041 in words is "thirteen billion, forty-three million, two hundred fifty-one thousand, forty-one".
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