Base | Representation |
---|---|
bin | 11101101010000011011001… |
… | …001110111100111100010001 |
3 | 122002211021220202201121210021 |
4 | 131222003121032330330101 |
5 | 114044004204110423213 |
6 | 1141224105022103441 |
7 | 36321326400055225 |
oct | 3552033116747421 |
9 | 562737822647707 |
10 | 130433211420433 |
11 | 38618461507329 |
12 | 127669b671ab81 |
13 | 57a1a506c539c |
14 | 242d0030c8785 |
15 | 1012d019c2d8d |
hex | 76a0d93bcf11 |
130433211420433 has 2 divisors, whose sum is σ = 130433211420434. Its totient is φ = 130433211420432.
The previous prime is 130433211420377. The next prime is 130433211420451. The reversal of 130433211420433 is 334024112334031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 130364489846529 + 68721573904 = 11417727^2 + 262148^2 .
It is a cyclic number.
It is not a de Polignac number, because 130433211420433 - 217 = 130433211289361 is a prime.
It is not a weakly prime, because it can be changed into another prime (130433211450433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65216605710216 + 65216605710217.
It is an arithmetic number, because the mean of its divisors is an integer number (65216605710217).
Almost surely, 2130433211420433 is an apocalyptic number.
It is an amenable number.
130433211420433 is a deficient number, since it is larger than the sum of its proper divisors (1).
130433211420433 is an equidigital number, since it uses as much as digits as its factorization.
130433211420433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 130433211420433 its reverse (334024112334031), we get a palindrome (464457323754464).
The spelling of 130433211420433 in words is "one hundred thirty trillion, four hundred thirty-three billion, two hundred eleven million, four hundred twenty thousand, four hundred thirty-three".
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