Base | Representation |
---|---|
bin | 11101101010000011011001… |
… | …001110111100111100100011 |
3 | 122002211021220202201121210221 |
4 | 131222003121032330330203 |
5 | 114044004204110423301 |
6 | 1141224105022103511 |
7 | 36321326400055252 |
oct | 3552033116747443 |
9 | 562737822647727 |
10 | 130433211420451 |
11 | 38618461507345 |
12 | 127669b671ab97 |
13 | 57a1a506c53b4 |
14 | 242d0030c8799 |
15 | 1012d019c2da1 |
hex | 76a0d93bcf23 |
130433211420451 has 2 divisors, whose sum is σ = 130433211420452. Its totient is φ = 130433211420450.
The previous prime is 130433211420433. The next prime is 130433211420461. The reversal of 130433211420451 is 154024112334031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130433211420451 - 227 = 130433077202723 is a prime.
It is not a weakly prime, because it can be changed into another prime (130433211420461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65216605710225 + 65216605710226.
It is an arithmetic number, because the mean of its divisors is an integer number (65216605710226).
Almost surely, 2130433211420451 is an apocalyptic number.
130433211420451 is a deficient number, since it is larger than the sum of its proper divisors (1).
130433211420451 is an equidigital number, since it uses as much as digits as its factorization.
130433211420451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 130433211420451 its reverse (154024112334031), we get a palindrome (284457323754482).
The spelling of 130433211420451 in words is "one hundred thirty trillion, four hundred thirty-three billion, two hundred eleven million, four hundred twenty thousand, four hundred fifty-one".
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