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13043347249 is a prime number
BaseRepresentation
bin11000010010111000…
…11010111100110001
31020200000100200201011
430021130122330301
5203203044102444
65554140110521
7641140423312
oct141134327461
936600320634
1013043347249
1155936a1929
122640235441
1312cb36ac6a
148ba410609
15515165734
hex30971af31

13043347249 has 2 divisors, whose sum is σ = 13043347250. Its totient is φ = 13043347248.

The previous prime is 13043347199. The next prime is 13043347319. The reversal of 13043347249 is 94274334031.

13043347249 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8182468849 + 4860878400 = 90457^2 + 69720^2 .

It is a cyclic number.

It is not a de Polignac number, because 13043347249 - 217 = 13043216177 is a prime.

It is not a weakly prime, because it can be changed into another prime (13043347049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521673624 + 6521673625.

It is an arithmetic number, because the mean of its divisors is an integer number (6521673625).

Almost surely, 213043347249 is an apocalyptic number.

It is an amenable number.

13043347249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13043347249 is an equidigital number, since it uses as much as digits as its factorization.

13043347249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 40.

The spelling of 13043347249 in words is "thirteen billion, forty-three million, three hundred forty-seven thousand, two hundred forty-nine".