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13043401123303 = 61213826247923
BaseRepresentation
bin1011110111001110011101…
…0010100110010111100111
31201011221022001101000211201
42331303213102212113213
53202200341141421203
643424020013143331
72514232432145515
oct275634722462747
951157261330751
1013043401123303
114179747991041
121567a9478ab47
13737cab567b75
143314381b34b5
1517944ea48e1d
hexbdce74a65e7

13043401123303 has 4 divisors (see below), whose sum is σ = 13257227371288. Its totient is φ = 12829574875320.

The previous prime is 13043401123261. The next prime is 13043401123451. The reversal of 13043401123303 is 30332110434031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13043401123303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13043401120303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106913123901 + ... + 106913124022.

It is an arithmetic number, because the mean of its divisors is an integer number (3314306842822).

Almost surely, 213043401123303 is an apocalyptic number.

13043401123303 is a deficient number, since it is larger than the sum of its proper divisors (213826247985).

13043401123303 is an equidigital number, since it uses as much as digits as its factorization.

13043401123303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213826247984.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 13043401123303 its reverse (30332110434031), we get a palindrome (43375511557334).

The spelling of 13043401123303 in words is "thirteen trillion, forty-three billion, four hundred one million, one hundred twenty-three thousand, three hundred three".

Divisors: 1 61 213826247923 13043401123303