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13043401440038 = 211815522185199
BaseRepresentation
bin1011110111001110011101…
…0011110011101100100110
31201011221022001222010022122
42331303213103303230212
53202200341232040123
643424020024025542
72514232434635114
oct275634723635446
951157261863278
1013043401440038
114179748088002
121567a949022b2
13737cab649098
14331438256ab4
1517944eaacbc8
hexbdce74f3b26

13043401440038 has 8 divisors (see below), whose sum is σ = 19581668719200. Its totient is φ = 6516178533640.

The previous prime is 13043401440031. The next prime is 13043401440049. The reversal of 13043401440038 is 83004410434031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×130434014400382 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13043401440031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2761090238 + ... + 2761094961.

It is an arithmetic number, because the mean of its divisors is an integer number (2447708589900).

Almost surely, 213043401440038 is an apocalyptic number.

13043401440038 is a deficient number, since it is larger than the sum of its proper divisors (6538267279162).

13043401440038 is a wasteful number, since it uses less digits than its factorization.

13043401440038 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5522186382.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 13043401440038 its reverse (83004410434031), we get a palindrome (96047811874069).

The spelling of 13043401440038 in words is "thirteen trillion, forty-three billion, four hundred one million, four hundred forty thousand, thirty-eight".

Divisors: 1 2 1181 2362 5522185199 11044370398 6521700720019 13043401440038