130434141340023 has 4 divisors (see below), whose sum is σ = 173912188453368. Its totient is φ = 86956094226680.

The previous prime is 130434141339989. The next prime is 130434141340033. The reversal of 130434141340023 is 320043141434031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130434141340023 - 2⁸ = 130434141339767 is a prime.

It is a super-4 number, since 4×130434141340023⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130434141340033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21739023556668 + ... + 21739023556673.

It is an arithmetic number, because the mean of its divisors is an integer number (43478047113342).

Almost surely, 2^{130434141340023} is an apocalyptic number.

130434141340023 is a deficient number, since it is larger than the sum of its proper divisors (43478047113345).

130434141340023 is an equidigital number, since it uses as much as digits as its factorization.

130434141340023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43478047113344.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 130434141340023 its reverse (320043141434031), we get a palindrome (450477282774054).

The spelling of 130434141340023 in words is "one hundred thirty trillion, four hundred thirty-four billion, one hundred forty-one million, three hundred forty thousand, twenty-three".