Base | Representation |
---|---|
bin | 11101101010000100010101… |
… | …011010001110110101011111 |
3 | 122002211101112010110002200111 |
4 | 131222010111122032311133 |
5 | 114044013241034312041 |
6 | 1141224353125110451 |
7 | 36321363406326643 |
oct | 3552042532166537 |
9 | 562741463402614 |
10 | 130434221010271 |
11 | 3861892a3900a2 |
12 | 12767038858427 |
13 | 57a1b8190c519 |
14 | 242d09b210c23 |
15 | 1012d6044a981 |
hex | 76a11568ed5f |
130434221010271 has 2 divisors, whose sum is σ = 130434221010272. Its totient is φ = 130434221010270.
The previous prime is 130434221010263. The next prime is 130434221010427. The reversal of 130434221010271 is 172010122434031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130434221010271 - 23 = 130434221010263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130434221010571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217110505135 + 65217110505136.
It is an arithmetic number, because the mean of its divisors is an integer number (65217110505136).
Almost surely, 2130434221010271 is an apocalyptic number.
130434221010271 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434221010271 is an equidigital number, since it uses as much as digits as its factorization.
130434221010271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
The spelling of 130434221010271 in words is "one hundred thirty trillion, four hundred thirty-four billion, two hundred twenty-one million, ten thousand, two hundred seventy-one".
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