Base | Representation |
---|---|
bin | 11101101010000100010110… |
… | …001100010100011010010111 |
3 | 122002211101120001011011201021 |
4 | 131222010112030110122113 |
5 | 114044013302414442221 |
6 | 1141224354314342011 |
7 | 36321363626043643 |
oct | 3552042614243227 |
9 | 562741501134637 |
10 | 130434234140311 |
11 | 38618936838972 |
12 | 1276704112a907 |
13 | 57a1b8455898a |
14 | 242d09cc6bc23 |
15 | 1012d61691041 |
hex | 76a116314697 |
130434234140311 has 2 divisors, whose sum is σ = 130434234140312. Its totient is φ = 130434234140310.
The previous prime is 130434234140291. The next prime is 130434234140321. The reversal of 130434234140311 is 113041432434031.
It is a strong prime.
It is an emirp because it is prime and its reverse (113041432434031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130434234140311 - 27 = 130434234140183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130434234140321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217117070155 + 65217117070156.
It is an arithmetic number, because the mean of its divisors is an integer number (65217117070156).
Almost surely, 2130434234140311 is an apocalyptic number.
130434234140311 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434234140311 is an equidigital number, since it uses as much as digits as its factorization.
130434234140311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 130434234140311 its reverse (113041432434031), we get a palindrome (243475666574342).
The spelling of 130434234140311 in words is "one hundred thirty trillion, four hundred thirty-four billion, two hundred thirty-four million, one hundred forty thousand, three hundred eleven".
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