Base | Representation |
---|---|
bin | 11101101010000100100010… |
… | …000000101000101000101011 |
3 | 122002211102001212020000101021 |
4 | 131222010202000220220223 |
5 | 114044014204143412021 |
6 | 1141224430120033311 |
7 | 36321401554210141 |
oct | 3552044200505053 |
9 | 562742055200337 |
10 | 130434432404011 |
11 | 38618a2874536a |
12 | 12767097602837 |
13 | 57a1bb6655888 |
14 | 242d0bb31b591 |
15 | 1012d73ca5c41 |
hex | 76a122028a2b |
130434432404011 has 2 divisors, whose sum is σ = 130434432404012. Its totient is φ = 130434432404010.
The previous prime is 130434432403943. The next prime is 130434432404047. The reversal of 130434432404011 is 110404234434031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130434432404011 is a prime.
It is not a weakly prime, because it can be changed into another prime (130434432404711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217216202005 + 65217216202006.
It is an arithmetic number, because the mean of its divisors is an integer number (65217216202006).
Almost surely, 2130434432404011 is an apocalyptic number.
130434432404011 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434432404011 is an equidigital number, since it uses as much as digits as its factorization.
130434432404011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 130434432404011 its reverse (110404234434031), we get a palindrome (240838666838042).
The spelling of 130434432404011 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred thirty-two million, four hundred four thousand, eleven".
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