Base | Representation |
---|---|
bin | 11101101010000100100010… |
… | …000000101000100111100111 |
3 | 122002211102001212020000021202 |
4 | 131222010202000220213213 |
5 | 114044014204143411233 |
6 | 1141224430120033115 |
7 | 36321401554210013 |
oct | 3552044200504747 |
9 | 562742055200252 |
10 | 130434432403943 |
11 | 38618a28745308 |
12 | 1276709760279b |
13 | 57a1bb6655835 |
14 | 242d0bb31b543 |
15 | 1012d73ca5be8 |
hex | 76a1220289e7 |
130434432403943 has 2 divisors, whose sum is σ = 130434432403944. Its totient is φ = 130434432403942.
The previous prime is 130434432403909. The next prime is 130434432404011. The reversal of 130434432403943 is 349304234434031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130434432403943 - 240 = 129334920776167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130434432403843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217216201971 + 65217216201972.
It is an arithmetic number, because the mean of its divisors is an integer number (65217216201972).
Almost surely, 2130434432403943 is an apocalyptic number.
130434432403943 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434432403943 is an equidigital number, since it uses as much as digits as its factorization.
130434432403943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4478976, while the sum is 47.
Adding to 130434432403943 its reverse (349304234434031), we get a palindrome (479738666837974).
The spelling of 130434432403943 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred thirty-two million, four hundred three thousand, nine hundred forty-three".
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