Base | Representation |
---|---|
bin | 1011110111001110100111… |
… | …0111101011111110111011 |
3 | 1201011221102001210201101112 |
4 | 2331303221313223332323 |
5 | 3202200433231300214 |
6 | 43424024200510535 |
7 | 2514233466042023 |
oct | 275635167537673 |
9 | 51157361721345 |
10 | 13043444400059 |
11 | 417976a35a557 |
12 | 1567aa717b44b |
13 | 737cb750b008 |
14 | 33143dc3aa83 |
15 | 179453746a3e |
hex | bdce9debfbb |
13043444400059 has 2 divisors, whose sum is σ = 13043444400060. Its totient is φ = 13043444400058.
The previous prime is 13043444400023. The next prime is 13043444400061. The reversal of 13043444400059 is 95000444434031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13043444400059 is a prime.
Together with 13043444400061, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13043444399989 and 13043444400025.
It is not a weakly prime, because it can be changed into another prime (13043444400079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6521722200029 + 6521722200030.
It is an arithmetic number, because the mean of its divisors is an integer number (6521722200030).
Almost surely, 213043444400059 is an apocalyptic number.
13043444400059 is a deficient number, since it is larger than the sum of its proper divisors (1).
13043444400059 is an equidigital number, since it uses as much as digits as its factorization.
13043444400059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 13043444400059 in words is "thirteen trillion, forty-three billion, four hundred forty-four million, four hundred thousand, fifty-nine".
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