Base | Representation |
---|---|
bin | 11101101010000100100010… |
… | …101101010101001111001111 |
3 | 122002211102002200021022010021 |
4 | 131222010202231111033033 |
5 | 114044014220143333124 |
6 | 1141224431215123011 |
7 | 36321402055620442 |
oct | 3552044255251717 |
9 | 562742080238107 |
10 | 130434444121039 |
11 | 38618a34318563 |
12 | 1276709b513467 |
13 | 57a1bb8bc8b26 |
14 | 242d0bcacb659 |
15 | 1012d74d1c7e4 |
hex | 76a122b553cf |
130434444121039 has 2 divisors, whose sum is σ = 130434444121040. Its totient is φ = 130434444121038.
The previous prime is 130434444121013. The next prime is 130434444121061. The reversal of 130434444121039 is 930121444434031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130434444121039 - 235 = 130400084382671 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130434444120986 and 130434444121004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130434444122039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65217222060519 + 65217222060520.
It is an arithmetic number, because the mean of its divisors is an integer number (65217222060520).
Almost surely, 2130434444121039 is an apocalyptic number.
130434444121039 is a deficient number, since it is larger than the sum of its proper divisors (1).
130434444121039 is an equidigital number, since it uses as much as digits as its factorization.
130434444121039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 43.
The spelling of 130434444121039 in words is "one hundred thirty trillion, four hundred thirty-four billion, four hundred forty-four million, one hundred twenty-one thousand, thirty-nine".
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