Base | Representation |
---|---|
bin | 10010111110110001100… |
… | …011111111100010001101 |
3 | 11121200202200100022020011 |
4 | 102332301203333202031 |
5 | 132332304121440242 |
6 | 2435113442553221 |
7 | 163144052600551 |
oct | 22766143774215 |
9 | 4550680308204 |
10 | 1304354093197 |
11 | 46319a976921 |
12 | 190961668811 |
13 | 960001a614c |
14 | 471b9953861 |
15 | 23de12e1d17 |
hex | 12fb18ff88d |
1304354093197 has 2 divisors, whose sum is σ = 1304354093198. Its totient is φ = 1304354093196.
The previous prime is 1304354093123. The next prime is 1304354093209. The reversal of 1304354093197 is 7913904534031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1269556548516 + 34797544681 = 1126746^2 + 186541^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1304354093197 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1304354093197.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1304354093897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652177046598 + 652177046599.
It is an arithmetic number, because the mean of its divisors is an integer number (652177046599).
Almost surely, 21304354093197 is an apocalyptic number.
It is an amenable number.
1304354093197 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304354093197 is an equidigital number, since it uses as much as digits as its factorization.
1304354093197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 49.
The spelling of 1304354093197 in words is "one trillion, three hundred four billion, three hundred fifty-four million, ninety-three thousand, one hundred ninety-seven".
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