130440000000401 has 16 divisors (see below), whose sum is σ = 161491488412800. Its totient is φ = 103205274713424.

The previous prime is 130440000000353. The next prime is 130440000000403. The reversal of 130440000000401 is 104000000044031.

It is not a de Polignac number, because 130440000000401 - 2¹⁴ = 130439999984017 is a prime.

It is a super-2 number, since 2×130440000000401² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 130440000000401.

It is not an unprimeable number, because it can be changed into a prime (130440000000403) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4240832531 + ... + 4240863288.

It is an arithmetic number, because the mean of its divisors is an integer number (10093218025800).

Almost surely, 2^{130440000000401} is an apocalyptic number.

It is an amenable number.

130440000000401 is a deficient number, since it is larger than the sum of its proper divisors (31051488412399).

130440000000401 is an frugal number, since it uses more digits than its factorization.

130440000000401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8481695865 (or 8481695839 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 130440000000401 its reverse (104000000044031), we get a palindrome (234440000044432).

The spelling of 130440000000401 in words is "one hundred thirty trillion, four hundred forty billion, four hundred one", and thus it is an aban number.