Base | Representation |
---|---|
bin | 1011110111010000101011… |
… | …1111001000100110111011 |
3 | 1201011222211210021010211112 |
4 | 2331310022333020212323 |
5 | 3202203103000003233 |
6 | 43424155245150535 |
7 | 2514253323420146 |
oct | 275641277104673 |
9 | 51158753233745 |
10 | 13044000000443 |
11 | 4179a24a42325 |
12 | 156802125b44b |
13 | 73807565c639 |
14 | 33149394705d |
15 | 1794873e4048 |
hex | bdd0afc89bb |
13044000000443 has 2 divisors, whose sum is σ = 13044000000444. Its totient is φ = 13044000000442.
The previous prime is 13044000000401. The next prime is 13044000000497. The reversal of 13044000000443 is 34400000044031.
It is a weak prime.
It is an emirp because it is prime and its reverse (34400000044031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13044000000443 - 26 = 13044000000379 is a prime.
It is not a weakly prime, because it can be changed into another prime (13044000000643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6522000000221 + 6522000000222.
It is an arithmetic number, because the mean of its divisors is an integer number (6522000000222).
Almost surely, 213044000000443 is an apocalyptic number.
13044000000443 is a deficient number, since it is larger than the sum of its proper divisors (1).
13044000000443 is an equidigital number, since it uses as much as digits as its factorization.
13044000000443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 13044000000443 its reverse (34400000044031), we get a palindrome (47444000044474).
The spelling of 13044000000443 in words is "thirteen trillion, forty-four billion, four hundred forty-three", and thus it is an aban number.
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