1304400000414 has 16 divisors (see below), whose sum is σ = 2981485715328. Its totient is φ = 372685714392.

The previous prime is 1304400000401. The next prime is 1304400000493. The reversal of 1304400000414 is 4140000044031.

It is a super-2 number, since 2×1304400000414² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15528571392 + ... + 15528571475.

It is an arithmetic number, because the mean of its divisors is an integer number (186342857208).

Almost surely, 2^{1304400000414} is an apocalyptic number.

1304400000414 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1304400000414 is an abundant number, since it is smaller than the sum of its proper divisors (1677085714914).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1304400000414 is a wasteful number, since it uses less digits than its factorization.

1304400000414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31057142879.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 1304400000414 its reverse (4140000044031), we get a palindrome (5444400044445).

The spelling of 1304400000414 in words is "one trillion, three hundred four billion, four hundred million, four hundred fourteen", and thus it is an aban number.