Base | Representation |
---|---|
bin | 11101101010001001101101… |
… | …111000001010101101110111 |
3 | 122002211221102220001101002010 |
4 | 131222021231320022231313 |
5 | 114044112110024020043 |
6 | 1141231150413415303 |
7 | 36321656542650654 |
oct | 3552115570125567 |
9 | 562757386041063 |
10 | 130440000220023 |
11 | 386203256189aa |
12 | 1276819019a533 |
13 | 57a2593021c70 |
14 | 242d488988c2b |
15 | 101309c9be133 |
hex | 76a26de0ab77 |
130440000220023 has 32 divisors (see below), whose sum is σ = 187523147298816. Its totient is φ = 80174483238528.
The previous prime is 130440000219961. The next prime is 130440000220051. The reversal of 130440000220023 is 320022000044031.
It is not a de Polignac number, because 130440000220023 - 216 = 130440000154487 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130440000270023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1019978761 + ... + 1020106637.
It is an arithmetic number, because the mean of its divisors is an integer number (5860098353088).
Almost surely, 2130440000220023 is an apocalyptic number.
130440000220023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130440000220023 is a deficient number, since it is larger than the sum of its proper divisors (57083147078793).
130440000220023 is a wasteful number, since it uses less digits than its factorization.
130440000220023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159063.
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 130440000220023 its reverse (320022000044031), we get a palindrome (450462000264054).
The spelling of 130440000220023 in words is "one hundred thirty trillion, four hundred forty billion, two hundred twenty thousand, twenty-three".
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