Base | Representation |
---|---|
bin | 11101101010001001101101… |
… | …111011100010011100000001 |
3 | 122002211221102221201021010211 |
4 | 131222021231323202130001 |
5 | 114044112110240303432 |
6 | 1141231150444354121 |
7 | 36321656553321022 |
oct | 3552115573423401 |
9 | 562757387637124 |
10 | 130440001103617 |
11 | 38620326071847 |
12 | 12768190545941 |
13 | 57a25932711ba |
14 | 242d488b38c49 |
15 | 101309cae5d47 |
hex | 76a26dee2701 |
130440001103617 has 2 divisors, whose sum is σ = 130440001103618. Its totient is φ = 130440001103616.
The previous prime is 130440001103603. The next prime is 130440001103669. The reversal of 130440001103617 is 716301100044031.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116191497574656 + 14248503528961 = 10779216^2 + 3774719^2 .
It is a cyclic number.
It is not a de Polignac number, because 130440001103617 - 223 = 130439992715009 is a prime.
It is not a weakly prime, because it can be changed into another prime (130440001103117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65220000551808 + 65220000551809.
It is an arithmetic number, because the mean of its divisors is an integer number (65220000551809).
Almost surely, 2130440001103617 is an apocalyptic number.
It is an amenable number.
130440001103617 is a deficient number, since it is larger than the sum of its proper divisors (1).
130440001103617 is an equidigital number, since it uses as much as digits as its factorization.
130440001103617 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 130440001103617 its reverse (716301100044031), we get a palindrome (846741101147648).
The spelling of 130440001103617 in words is "one hundred thirty trillion, four hundred forty billion, one million, one hundred three thousand, six hundred seventeen".
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